QUESTION: 81

What happens when you attempt to compile and run the following code?

#include <iostream>
#include <algorithm>
#include <vector>
#include <set>
using namespace std;

int main() {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
vector<int> v1(t, t + 15);
set<int> s1(t, t + 15);

pair<set<int>::iterator, vector<int>::iterator > resultSet = mismatch(s1.begin(), s1.end(), v1.begin());
cout<<*resultSet.first<<" "<<*resultSet.second<<endl;

return 0;
}

Program outputs:

2 4
4 2
0 5
compilation error

Answer(s): B

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QUESTION: 82

Which changes introduced independently will allow the code to compile and display 0 0 1 1 8 8 9 9 (choose all that apply)?

#include <iostream>
#include <set>
#include <vector>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}

/* Insert Code Here 1 */
};
/* Insert Code Here 2*/

int main(){
A t[] = { 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
set<A> s(t, t+10); /* Replace Code Here 3 */
multiset<A> s1(s.begin(),s.end()); /* Replace Code Here 4 */
s1.insert(s.begin(),s.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
multiset<A>::iterator i=s1.begin(); /* Replace Code Here 5 */
for( ;i!= s1.end(); i++)
{
cout<<i?>getA()<<" ";
}
cout<<endl;
return 0;
}

operator int() const { return a;} inserted at Place 1
bool operator < (const A & b) const { return a<b.a;} inserted at Place 1
bool operator < (const A & b) const { return b.a<a;} inserted at Place 1
struct R { bool operator ()(const A & a, const A & b) { return a.getA()<b.getA();} }; inserted at Place 2
replacing line marked 3 with set<A, R> s(t, t+10);
replacing line marked 4 with multiset<A,R> s1(s.begin(),s.end());
replacing line marked 5 with multiset<A,R>::iterator i=s1.begin();

Answer(s): A,B,D

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QUESTION: 83

What happens when you attempt to compile and run the following code?

#include <deque>
#include <iostream>
#include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};
deque<int> d1(t, t+10);
deque<int>::iterator it = lower_bound(d1.begin(), d1.end(), 4);
for_each(it, d1.end(), Out<int>(cout));cout<<endl;
return 0;
}

Program outputs:

8 10 5 1 4 6 2 7 9 3
4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
compilation error
1 2 3 4

Answer(s): A

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QUESTION: 84

What happens when you attempt to compile and run the following code? Choose all that apply.

#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
#include <iomanip>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};

template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };

int main () {
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out", ios::trunc|ios::out);
list<B> l(t, t+10);
for_each(l.begin(), l.end(), Out<B>(f));
f.close();
f.open("test.out");
for( ; f.good() ; ) {
int i;
f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}

file test.out will be opened writing
file test.out will be truncated
file test.out will be opened for reading
no file will be created nor opened
program will display sequence 1 2 3 4 5 6 7 8 9 10

Answer(s): A,B,C,E

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