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CFA Level I Chartered Financial Analyst Questions 1131–1135 (page: 228)

Updated On: 9-Feb-2026

The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. A sample of the weights of 40 trout revealed that the mean weight is 402.7 grams and the standard deviation 8.8 grams. What is the point estimate?

  1. None of these answers
  2. 10.0675
  3. 8.8
  4. 40
  5. 402.7

Answer(s): E

Explanation:

The sample mean is a good estimate for the population mean.



Given the following points: (-2, 0), (-1,0), (1, 1) and (2, 3) If the regression equation is Y' = 2 - .4X, what is the value of Y when X = -3?

  1. None of these answers
  2. 3.2
  3. -10.0
  4. 0.8
  5. 14.0

Answer(s): B

Explanation:

Y' = 2 - 0.4*(-3) = 2 + 1.2 = 3.2



What must you know to develop a binomial probability distribution?

  1. Probability of success
  2. Probability of success and number of trials
  3. Probability of success and number of successes
  4. Number of trials
  5. Number of successes

Answer(s): B

Explanation:

Binomial distribution: n!(p^r)(q^(n-r))/r!(n-r)!. We need to know n and p. q = 1-p. r is the number of successes which we determine ourselves.



The weights of a sample of crates ready for shipment to Laos are (in kilograms): 103, 97, 101, 106 and 103.
What is the mean deviation?

  1. 2.4 kg
  2. 102.0 kg
  3. 0 kg
  4. None of these answers
  5. 6.9 kg

Answer(s): A

Explanation:

The mean is 102. The mean deviation is the absolute values of the deviation from the mean. (1 + 5 + 1 + 4 +
1)/5 = 12/5 = 2.4



What is the distribution with a mean of 0 and a standard deviation of 1 called?

  1. Binomial probability distribution
  2. None of these answers
  3. Frequency distribution
  4. Z-score
  5. Standard normal distribution

Answer(s): E

Explanation:

These values describe the standard normal distribution.



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