Free CPP Exam Braindumps
C++ Certified Professional Programmer Questions 56–60 (page: 13)

What happens when you attempt to compile and run the following code?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };

int main() {
int t1[]={1,2,3,4,5,6,7,8,9,10};
int t2[]={1,2,3,4,5,6,7,8,9,10};
vector<int> v1(t1, t1+10);
vector<int> v2(t2, t2+10);
vector<int> v3(10);
transform(v1.begin(), v1.end(), v2.rbegin(), v3.begin(), minus<int>());
for_each(v3.rbegin(), v3.rend(), Out<int>(cout));cout<<endl;
return 0;
}

Program outputs:

What happens when you attempt to compile and run the following code?

#include <vector>
#include <iostream>
#include <algorithm>
#include <functional>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };

struct Add : public binary_function<int, int, int> {
int operator() (const int & a, const int & b) const {
return a+b;
}
};
int main() {
int t[]={1,2,3,4,5,6,7,8,9,10};
vector<int> v1(t, t+10);
vector<int> v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(Add(), 1));
for_each(v2.rbegin(), v2.rend(), Out<int>(cout));cout<<endl;
return 0;
}

Program outputs:

Which changes introduced independently will allow the code to compile and display “one” “eight” “nine” “ten”? Choose all that apply.

#include <iostream>
#include <map>
#include <string>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
int t[] = { 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string s[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","ten"};
multimap<A,string> m; /* Replace Code Here 3 */
for(int i=0; i<10; i++) {
m.insert(pair<A,string>(A(t[i]),s[i]));
}
m.erase(m.lower_bound(2),m.upper_bound(7));
multimap<A, string>::iterator i=m.begin(); /* Replace Code Here 4 */
for( ; i!= m.end(); i++) {
cout<<i?>second<<" ";
}
cout<<endl;
return 0;
}

What happens when you attempt to compile and run the following code?

#include <iostream>
#include <algorithm>
#include <map>
using namespace std;

int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
map<int, int> m;
for(int i=0; i < 10; i++) {
m[i]=t[i];
}
map<int, int>::iterator it = find(m.begin(), m.end(), 5);
cout<<it?>first;
return 0;
}

Program outputs:

What happens when you attempt to compile and run the following code? Choose all that apply.

#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
#include <iomanip>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };
int main () {
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out", ios::trunc|ios::out);
list<int> l(t, t+10);
for_each(l.begin(), l.end(), Out<int>(f));
f.close(); f.open("test.out");
for( ; f.good() ; ) {
int i; f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}