Last month of a family's monthly budget was used for food and rent. If of the family's monthly budget was used for food, what fraction of the family's monthly budget was used for rent?
Answer(s): B
Let R be the fraction for rent.
If , what is the value of n-1 + k-1?
Answer(s): C
x, 6, 14, 10, 11In the list shown, x is an integer less than or equal to 6. If the range of the numbers in the list is greater than the median, what is the greatest possible value of x?
Given the list: x, 6, 14, 10, 11x is an integer and x 6We need the greatest possible value of x such that range > median Let's try the largest possible x first: x = 6List: 6, 6, 10, 11, 14Median is the middle value: 10Range = 14 - 6 = 8Check: 8 > 10? No.Try x = 5List: 5, 6, 10, 11, 14Median = 10Range = 14 - 5 = 9Check: 9 > 10? No.Try x = 4List: 4, 6, 10, 11, 14Median = 10Range = 14 - 4 = 10Check: 10 > 10? No (it's equal, not greater).Try x = 3List: 3, 6, 10, 11, 14Median = 10Range = 14 - 3 = 11Check: 11 > 10? Yes.So the greatest possible value is 3.
A hotel offers a 20 percent discount on the regular price of each room, and the hotel charges a 15 percent sales tax on the discounted price. If a guest rented a room for one night at the discounted price and paid a total of p dollars, including the sales tax, what is the regular price, in dollars, of the room?
Let the regular price be x.20% discount means discounted price = 0.8x15% sales tax on the discounted price means total paid = 0.8x × 1.15 = 0.92x The total paid is p:0.92x = p
A computer is programmed to generate all ordered pairs (x, y) for which x and y are positive integers, 1 x 8, and y x. How many different ordered pairs (x, y) will be generate:
x can be any integer from 1 to 8 (inclusive).For each x, y can be any positive integer such that 1 y x.So, for each value of x, the number of possible y values is x.Total pairs = sum of x as x goes from 1 to 8:
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