If x is positive and 50 percent greater than y and if y is 30 percent greater than z, then x is what percent greater than z?
Answer(s): E
y is 30 percent greater than z, so y = 1.3z x is 50 percent greater than y, so x = 1.5y = 1.5 × 1.3z = 1.95z x - z = 1.95z - z = 0.95z
At a certain company, employees who earn $20.00 per hour will be given an increase of $1.00 per hour. For each of the other employees, either the employee will be given an increase of $1.00 per hour or the employee will be given a percent increase equal to the percent increase that will be given to the employees who earn $20.00 per hour, whichever results in a larger increase for that employee. Which of the following statements are true?Indicate all such statements.
Answer(s): A,B,C
Percent increase for $20/hr employeeAll other employees get the larger of:a $1.00 increase, or a 5% increase.1. Employee earns less than $20/hr. For example,Thus, such employees get more than 5%.2. Employee earns $22.00/hr.5% of $22.00 = $1.10$1.10 > $1.00, so this employee will get $1.10/hr increase.3. Employee earns $24.00/hr.5% of $24.00 = $1.20$24.00 + $1.20 = $25.20/hr after the increase.
FILL BLANK
Answer(s): A
Use inclusion-exclusion principle:Percent offering at least one = (health) + (pension) - (both) 58% + 46% - 32% = 72%Percent offering neither = 100% - 72% = 28%As a fraction: 28% = 28/100 =
When the integer n is divided by 33, the remainder is 6. Which of the following must be a divisor of n?
Answer(s): D
Since n leaves a remainder of 6 when divided by 33, we can write n = 33k + 6 for some integer k.A number that must always divide n is any common divisor of both 33 and 6, because n = 33k + 6 = 3(11k + 2).The greatest common divisor of 33 and 6 is 3, and no larger number in the choices divides every such n. (For example, n might be 6 when k = 0, so 12, 10, 8, or 2 would not always divide.) Hence 3 is a divisor of every possible n.
For all numbers a and b, the operation is defined by the following equation.What is the value of ((1 2) 1) 2?
1. ComputeSince 1 < 2, use the rule "a < b result = b + 1."So2. ComputeSince 3 > 1, use the rule "a > b result = 2."So3. ComputeBecause 2 = 2, use the rule "a = b result = 0."So
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