Free ASVAB Section 2: Arithmetic Reasoning Exam Braindumps
ASVAB Section two : Arithmetic Reasoning Questions 66–70 (page: 15)

Updated On: 9-Feb-2026

The price of daily admission at an amusement park is $36. The park sells an unlimited season pass for $240.
How many trips would you need to make with the season ticket in order for it to cost less than paying the daily admission rate?

  1. 6
  2. 7
  3. 8
  4. 9

Answer(s): B

Explanation:

Let x equal the number of daily tickets you would purchase. 36x = the daily ticket cost. 240 < 36x
240/36 < x
62⁄3 < x
You would need to use the ticket more than 62⁄3 times (or 7 times) in order for it to be cheaper to use the season ticket.



A plumber needs four lengths of pipe, each 3-feet, 6-inches long. Pipes are sold by the foot. How many feet does he need to buy?

  1. 15
  2. 16
  3. 14
  4. 12

Answer(s): C

Explanation:

Convert the pipe length to inches: 3 feet, 6 inches = 42 inches. Multiply 42 inches by the number of pipes needed to find the number of inches of pipe needed: 42 × 4 = 168. Divide the total amount of pipe needed in inches by 12 to determine how many feet of pipes are needed: 168 ÷ 12 = 14.



The product of two consecutive odd numbers is 399. What are the numbers?

  1. 17 and 19
  2. 19 and 21
  3. 21 and 23
  4. 25 and 27

Answer(s): B

Explanation:

The fastest way to solve this would be to simply multiply the possible choices together (19 × 21 = 399). You can also solve this with algebra.



A personal trainer earns a 65% commission on her training sales.
If she sells $530.00 worth of training, how much commission does she make?

  1. $874.50
  2. $34.45
  3. $344.50
  4. $185.50

Answer(s): C

Explanation:

Multiply her total sales by her percent commission to find her commission: $530.00 × 0.65 = $344.50.



A rectangle is one inch longer than it is wide. Its diameter is five inches. What’s the width of the rectangle?

  1. 2 inches
  2. 3 inches
  3. 4 inches
  4. 5 inches

Answer(s): B

Explanation:

The diagonal formula for a rectangle is D2 = L2 + W2. In this case, D = 5, and L = W + 1. Substituting the known values into the formula results in 52 = (W + 1)2 + W2.
25 = (W + 1)(W + 1) + W2
25 = W2 + 2W + 1 + W2
25 = 2W2 + 2W + 1
(Note: This equation is a quadratic equation and can be solved by setting it equal to zero and factoring.) 0 = 2W2 + 2W – 24
1⁄2(0) = 1⁄2(2 W2 + 2W – 24)
0 = W2 + W – 12
0 = (W – 3)(W + 4)
W – 3 = 0W + 4 = 0
W = 3
W = –4 (not a possible solution)



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