"Tires R' us" have 4 times more tires for sale than any regular tire shop. If "Tires R' Us" Sells 122 tires, they will have only three times more tires than the rest.How many more tires do "Tires R' us" have than the regular tire shop?
Answer(s): C
Let's write the equations that come from the data: define x as the number of tires of "Tires R' us" and y as number of tires of the regular shop.X = 4Y and X – 122 = 3Y X= 488, Y=122. X – Y = 366.
If 512 = (A + 48)3, then (A + 53) is equal to
Answer(s): A
If 512 = (A + 48)3 A + 48 = 8 A = -40.Therefore, A + 53 = 13.
If 529 = (Y – 7)2, then Y/3 is equal to
Answer(s): D
529 = (Y – 7)2, take the root out of both sides to get 23 = Y – 7 □ Y = 30. Therefore, Y/3 is equal to 10.
The East-17 pre-school is upgrading all of his classrooms by buying 46 computers, 6 printers and 5 fax machines. If a computer costs 4 times more than a printer and 2 times more than the fax machine, what percent of the cost of the entire purchase was the cost of one computer, 2 printers and 1 fax machine?
Let's define the price of a printer as X, the computer costs 4X and the fax costs 2X. The total price of all the merchandise is (46 x 4)X + 6X + 10X = 200X.The specific group that was asked upon is worth 4X + 2X + 2X = 8X. The percentage of the price is (8/200) 4%.
A newly wed couple is designing their new house by purchasing 10 chairs, 3 desks, 3 televisions and 4 closets. If the price ratio between the new merchandise is 1 : 3 : 4 : 4, what fraction of the cost of the entire purchase was the cost of a desk and a closet?
Answer(s): B
Let X be the price of a single chair, normalize all the prices to the price of a chair. The total price of the entire purchase is: 10X + 9X + 12X + 16X = 47X.The specific purchase costs: 3X + 4X = 7X. The percent required is 7/47.
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