The running speed of a horse is three times faster than the jogging of a donkey.If a horse is running for 4 hours and a donkey is jogging for 3 hours, what is the horse’s speed (in Km/h) if the sum of their distances is 45 Km?
Answer(s): B
X is the donkey’s speed and 3X is the horse’s speed. The total amount of distance is Equal to 45 and to 3X x 4 + X x 3 = 15X ---> X = 3, the speed of a horse is 9.
Two ants are moving from their farms towards each other. Ant A is moving at a speed of 9 Cm per hour and ant B is moving at a speed of 6 Cm per hour. If the farms are 60 Cm away from each other, what will be the distance ant A travels until meeting ant B?
Answer(s): C
The ants are moving towards each other, therefore adding their speeds will represent the speed that they are moving towards one another. 60 Cm / (9 + 6) = 4 hours.The distance that ant A will travel in 4 hours is 4 x 9 = 36 Cm.
At 12:10 o’clock Bill leaves point A towards point B at a speed of 30 Km/h.At 13:40 o’clock Richi leaves from the same point towards point B also, but at a speed of 60 Km/h. At what time will Richi passes over Bill?
At 13:40, Bill has already moved (30 x 1.5) 45 Km.Their relative speed is (60 – 30) 30 Km/h; therefore, it would take (45 / 30) 1.5 hours to close the gap between the two. 13:40 + 90 minutes are 15:10.
James can eat 25 marshmallows is 20 minutes. Dylan can eat 25 in one hour. In how much time will the two eat 150 marshmallows?
Calculate each of their output in one hour: James can eat 75 and Dylan can eat only 25.Together they can eat 100 marshmallows in 1 hour. It would take those 1.5 hours to eat 150 marshmallows.
A wolf eats 5.5 Kg of meat in 2 days. A baby tiger eats 3 Kg of meat in 4 days. How much meat can the two combined eat in three days?
A wolf eats 2.25 Kg a day; a baby tiger eats 0.75 Kg a day. Together they eat 3 Kg of meat every day, in three days they will eat 9 Kg of meat.
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