The average (arithmetic mean) of the numbers of households that used oil and wood as types of heating was approximately what percent of the average of the numbers of households that used the remaining 6 types of heating?
Answer(s): D
To solve this problem, we need to compute the average number of households that used oil and wood as types of heating, and compare it to the average of the remaining 6 types of heating.Total number of households = 96 million.Households using oil = 96,000,000 × 13.1% = 12,576,000Households using wood = 96,000,000 × 5.0% = 4,800,000Households using the remaining 6 types of heating are:- Natural Gas = 96,000,000 × 51.3% = 49,248,000- Electricity = 96,000,000 × 24.8% = 23,808,000- Liquefied Gas = 96,000,000 × 4.0% = 3,840,000- Kerosene = 96,000,000 × 1.2% = 1,152,000- Coal = 96,000,000 × 0.4% = 384,000- Solar Power = 96,000,000 × 0.2% = 192,000The average of households using oil and wood is calculated as follows:The average of households using the remaining 6 types of heating is calculated as follows:Now, we compare the average of households using oil and wood to the average of the remaining 6 types:This is approximately 66% of the average of the remaining 6 types of heating.
FILL BLANKThe number of United States households in year Z was 1.6 percent greater than that in year Y. If 0.9 percent ofUnited States households in year Z used kerosene as a type of heating, then the number of households that used kerosene as a type of heating in year Z was what percent of the number of households that used kerosene as a type of heating in year Y?Give your answer to the nearest whole percent. (Enter your answer as an integer or a decimal in the answer box. Backspace to erase.)
Answer(s): A
We know the total number of households in year Y is 96 million, based on the previous information.From the table, we know that 1.2% of U.S. households in year Y used kerosene as a type of heating.The number of households using kerosene in year Y is:96,000,000 × 1.2% = 96,000,000 × 0.012 = 1,152,000 households.We are told that the number of households in year Z is 1.6% greater than in year Y. Therefore, the total number of households in year Z is:96,000,000 × (1 + 1.6%) = 96,000,000 × 1.016 = 97,536,000 households.We are also told that 0.9% of the U.S. households in year Z used kerosene as a type of heating. The number of households using kerosene in year Z is:97,536,000 × 0.9% = 97,536,000 × 0.009 = 877,824 households.To find what percent the number of households using kerosene in year Z is of the number in year Y, we divide the number of households in year Z (877,824) by the number in year Y (1,152,000), and then multiply by 100:Rounding to the nearest whole percent, the result is 76%.
Which of the following categories accounted for an amount closest to 10 percent of the total per-pupil spending?
Answer(s): C
The total per-pupil spending is $5,901. To find 10% of this amount:10% of 5,901 = 5,901 × 0.10 = $590.1Now, comparing this to the category expenditures:Instruction: $3,590School Operation and Maintenance: $612Administration: $512Student Services: $504Food Services and Other: $438Transportation: $245The amount closest to $590.1 is $612 for School Operation and Maintenance.
If the total per-pupil spending for Transportation and Food Services and Other was 10 percent greater for the school year 1994-1995 than for the school year 1993-1994, approximately what was the total per-pupil spending for these two categories for the school year 1993-1994?
For the school year 1994-1995, the total spending on Transportation and Food Services and Other is:Transportation ($245) + Food Services and Other ($438) = $683 It is given that this spending was 10% greater than in 1993-1994. Let the 1993-1994 spending be X.Since the 1994-1995 amount is 10% more than 1993-1994, we set up the equation:X + 0.10X = 6831.10X = 683X = 683/1.10X 621.82Rounding to the nearest dollar, the total per-pupil spending for these two categories in 1993-1994 was approximately $620.
The sectors of the pie chart are to be reordered so that their sizes decrease when viewed consecutively in a clockwise direction starting with the largest. If the sectors are to be reordered by interchanging the positions of adjacent sectors, one interchange at a time, until the desired order is achieved, what is the minimum number of interchanges that will be required?
Answer(s): E
From the pie chart, the sectors appear in this order (moving clockwise):1. Instruction ($3,590)2. Food Services and Other ($438)3. Transportation ($245)4. School Operation and Maintenance ($612)5. Administration ($512)6. Student Services ($504)The correct order in decreasing size should be:1. Instruction ($3,590)2. School Operation and Maintenance ($612)3. Administration ($512)4. Student Services ($504)5. Food Services and Other ($438)6. Transportation ($245)We now rearrange the sectors step by step by swapping adjacent sectors:1. Swap Food Services and Other ($438) with School Operation and Maintenance ($612) New order:Instruction, School Operation and Maintenance, Food Services and Other, Transportation, Administration,Student Services2. Swap Food Services and Other ($438) with Administration ($512) New order: Instruction, School Operation and Maintenance, Administration, Food Services and Other, Transportation, Student Services3. Swap Food Services and Other ($438) with Student Services ($504) New order: Instruction, School Operation and Maintenance, Administration, Student Services, Food Services and Other, Transportation4. Swap Transportation ($245) with Food Services and Other ($438) New order: Instruction, School Operation and Maintenance, Administration, Student Services, Transportation, Food Services and Other5. Swap Transportation ($245) with Student Services ($504) New order: Instruction, School Operation and Maintenance, Administration, Transportation, Student Services, Food Services and Other6. Swap Transportation ($245) with Administration ($512) New order: Instruction, School Operation and Maintenance, Transportation, Administration, Student Services, Food Services and Other7. Swap Transportation ($245) with School Operation and Maintenance ($612) Final correct order:Instruction, School Operation and Maintenance, Administration, Student Services, Food Services and Other, TransportationThe minimum number of adjacent interchanges required is seven.
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