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GRE GRE Test Exam Questions
Graduate Record Examination Test: Verbal, Quantitative, Analytical Writing (Page 15 )

Updated On: 10-Mar-2026
Page 15 of 119
PDF with 793 Questions



According to the data in the graph, approximately what is the average (arithmetic mean) annual decrease from 1980 to 1995 in the list price of a Brand X microcomputer?

  1. $200
  2. $400
  3. $700
  4. $1,000
  5. $1,500

Answer(s): A

Explanation:

The average annual decrease is calculated as:



Price in 1980 = $5,000 (slightly above $5,000 as observed)
Price in 1995 = $2,000
Years between 1980 and 1995 = 1995 - 1980 = 15 years
Total decrease = Price in 1980 - Price in 1995 = 5000 - 2000 = 3000





The graph shows the net income of a company for each of 6 years. For which of the following one-year time intervals was the percent increase or percent decrease in the net income greater than or equal to 50 percent? (Choose all that apply.)

  1. 1995-1996
  2. 1996-1997
  3. 1997-1998
  4. 1998-1999
  5. 1999-2000

Answer(s): A,C,E

Explanation:

To determine which one-year time intervals saw a percent increase or decrease in net income greater than or equal to 50%, we can use the formula for percent change:



Calculate the percent changes for each interval:
1. 1995-1996:
Net income in 1995 = 1.0 million

Net income in 1996 = 1.5 million




2. 1996-1997:
Net income in 1996 = 1.5 million

Net income in 1997 = 1.0 million



3. 1997-1998:
Net income in 1997 = 1.0 million

Net income in 1998 = 2.0 million



4. 1998-1999:
Net income in 1998 = 2.0 million

Net income in 1999 = 1.1 million



5. 1999-2000:
Net income in 1999 = 1.1 million

Net income in 2000 = 0.5 million



Determine which intervals have a percent change greater than or equal to 50% 1995-1996: 50% increase

1996-1997: -33.33% decrease (not greater than or equal to 50%)

1997-1998: 100% increase (greater than 50%)

1998-1999: -45% decrease (not greater than or equal to 50%)

1999-2000: -54.55% decrease (greater than 50% decrease)





The figure shows a normal distribution with mean m and standard deviation d, including approximate probabilities corresponding to the six intervals shown.

The distribution of the continuous random variable T is normal with mean 36.5. If P(36.5 < T < 43.9) = 0.475, which of the following is the best estimate of the standard deviation of the distribution of T?

  1. 1.8
  2. 3.7
  3. 7.4
  4. 11.1
  5. 14.8

Answer(s): B

Explanation:

The problem refers to a normal distribution where the mean is 36.5. The probability P(36.5 < T < 43.9) = 0.475 means that the area between 36.5 and 43.9 under the normal distribution curve is 0.475.
This is approximately the area under the curve between the mean and a value 7.4 units away from the mean (since 43.9 - 36.5 = 7.4). Thus, we are looking for an estimate of the standard deviation such that the area from the mean to 43.9 corresponds to approximately 0.475 of the total area.
In a standard normal distribution, the area between the mean and one standard deviation is approximately 0.3413. Since we are looking for the area from the mean to 43.9 (which is 7.4 units away), this distance is likely a multiple of the standard deviation.
From the chart and common normal distribution tables, a distance of 7.4 units corresponds approximately to 2 standard deviations in a standard normal distribution.
Since the distance from the mean (36.5) to 43.9 is 7.4 units, and this distance represents approximately 2 standard deviations, we can estimate the standard deviation d as:



The first term in sequence R is 5, and each succeeding term is 2 greater than the previous term.
What is the 83rd term in R?

  1. 90
  2. 123
  3. 147
  4. 169
  5. 171

Answer(s): D

Explanation:

The given sequence is an arithmetic sequence, where the first term a1 = 5, and the common difference d = 2.
The formula for the n-th term of an arithmetic sequence is:
an = a1 + (n - 1) × d a83 = 5 + (83 - 1) × 2

a83 = 5 + (83 - 1) × 2
a83 = 5 + 164
a83 = 169
Thus, the 83rd term in the sequence is 169.



The number of different subsets of 4 elements that can be selected from a set of 6 elements is 15. How many more different subsets of 4 elements can be selected from a set of 8 elements than from a set of 6 elements?

  1. 55
  2. 35
  3. 20
  4. 9
  5. 8

Answer(s): A

Explanation:



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