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Graduate Record Examination Test: Verbal, Quantitative, Analytical Writing Questions 211–215 (page: 44)

Updated On: 10-Feb-2026

A sales representative's monthly earnings consist of a base salary of $3,500 plus a commission equal to 5 percent of monthly sales in excess of $50,000.

If monthly sales total s dollars and s > $50,000, what are the sales representative's monthly earnings in terms of s, in dollars?

  1. 0.05s + 1,000
  2. 0.05s + 3,500
  3. 0.05(s - 3,500)
  4. 0.05(s - 50,000)
  5. 0.05(s - 53,500)

Answer(s): A

Explanation:

3500 + 0.05(s - 50,000) = 3500 + 0.05s - 2500 = 0.05s + 1000



All of the 80 science students at a certain school are enrolled in at least one of three science courses: biology, chemistry, and physics. There are 60 students enrolled in biology, 50 students enrolled in chemistry, and 35 students enrolled in physics. None of the students are enrolled in all three courses.

Which of the following could be the number of students enrolled in both chemistry and physics? (Choose all that apply.)

  1. 0
  2. 5
  3. 10
  4. 15
  5. 20
  6. 25
  7. 30
  8. 35

Answer(s): B,C,D,E

Explanation:

Let B, C, and P be the sets of students in biology, chemistry, and physics.
We know:
|B| = 60, |C| = 50, |P| = 35

Total students = 80

No student is in all three courses.

By inclusion­exclusion (with no triple intersection):



Let CP be the number of students in both chemistry and physics. We must have nonnegative counts in each category and not exceed course totals. This leads to the constraints:
CP 5

BP 15

BP + CP 35

15 BP + CP 35

Checking each answer choice for CP:
0: violates CP 5 not possible.

5: choose BP = 15 BP + CP = 20 (valid), yields consistent nonnegative counts possible.

10: choose BP = 15 BP + CP = 25 (valid) possible.

15: choose BP = 15 BP + CP = 30 (valid) possible.

20: choose BP = 15 BP + CP = 35 (valid) possible.

25, 30, 35: no BP 15 satisfies BP + CP 35 not possible.

Thus, the values that could be the number of students enrolled in both chemistry and physics are 5, 10, 15, and 20.



The average (arithmetic mean) of the hourly salaries of Ted and Bill is $8.50. Mary and Margaret each have an hourly salary of $8.50.

Quantity A
The average of the hourly salaries of Ted, Bill, Mary, and Margaret

Quantity B
The median of the hourly salaries of Ted, Bill, Mary, and Margaret

  1. Quantity A is greater.
  2. Quantity B is greater.
  3. The two quantities are equal.
  4. The relationship cannot be determined from the information given.

Answer(s): D

Explanation:

Ted and Bill's average is $8.50, so



Mary and Margaret each earn $8.50.
The four salaries are T, B, 8.5, 8.5.
Quantity A (the mean):



The mean is always $8.50, no matter what Ted and Bill individually earn.
Quantity B (the median):
The median depends on whether T and B are above or below 8.5:
If both T and B are greater than 8.5 median > 8.5 B > A

If both are less than 8.5 median < 8.5 A > B

If one is above and one below 8.5 median = 8.5 A = B

All scenarios are possible because only T+B=17T + B = 17T+B=17 is fixed.





Quantity A
The length of AD

Quantity B
The length of BC

  1. Quantity A is greater.
  2. Quantity B is greater.
  3. The two quantities are equal.
  4. The relationship cannot be determined from the information given.

Answer(s): B

Explanation:

AD and BC rise from the same base DC to the parallel top AB, so their vertical height is the same (call it h).
AD forms a 65° angle with DC AD = h / sin 65°.
BC forms a 62° angle with DC BC = h / sin 62°.
Since sin 65° > sin 62°, dividing by the larger sine gives the shorter length, so AD < BC.
Thus, Quantity B (BC) is greater.



a > b > 0 and k > 0

Quantity A



Quantity B

  1. Quantity A is greater.
  2. Quantity B is greater.
  3. The two quantities are equal.
  4. The relationship cannot be determined from the information given.

Answer(s): A

Explanation:



a(b + k) = ab + ak > ab + bk = b(a+ k) because a > b and k > 0; therefore



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