A study of the scores on an in-plant course in management principles and the years of service of the employees enrolled in the course resulted in these statistics:
Mean test score was 200 with a standard deviation of 40
Mean number of years of service was 20 years with a standard deviation of 2 years
In comparing the relative dispersion of the two distributions, what are the coefficients of variation (CV)?
- Test 50%, service 60%
- Test 35%, service 45%
- Test 100%, service 400%
- Test 20%, service 10%
- None of these answers
Answer(s): D
Explanation:
The respective CVs are found from (s*100)/mean. Test: 40*100/200 = 20% and Service: 2*100/20 = 10%.
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