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Test Prep GMAT Test Exam
Graduate Management Admission Test: Analytical Writing Assessment (AWA), Quantitative section, Verbal section (Page 3 )

Updated On: 19-Jan-2026
Page 3 of 147
PDF with 745 Questions

Is ?
(1) 3x = 6y
(2)

  1. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
  2. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
  3. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
  4. The problem can be solved using EITHER statement (1) only or statement (2) only.
  5. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.

Answer(s): D

Explanation:

Divide both sides of the equation in statement (1) by 3y. This results in the proportion.
Since , . Therefore, the answer to the original question would be yes. Statement (2) tells you that x/y is greater than 1; therefore, it must be an improper fraction. y/x would then be a proper fraction making it less than x/y. Either statement is sufficient.



What is the total cost of six pencils and four notebooks?

(1) Ten pencils and nine notebooks cost $11.50.
(2) Twelve pencils and eight notebooks cost $11.00.

  1. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
  2. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
  3. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
  4. The problem can be solved using EITHER statement (1) only or statement (2) only.
  5. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.

Answer(s): B

Explanation:

Statement (2) is the same as the original question doubled. Divide $11.00 by 2 to answer the question. Statement (1) is not sufficient by itself.



What is the ratio of the corresponding sides of two similar triangles?

(1) The ratio of the perimeters of the two triangles is 3:1.
(2) The ratio of the areas of the two triangles is 9:1.

  1. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
  2. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
  3. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
  4. The problem can be solved using EITHER statement (1) only or statement (2) only.
  5. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.

Answer(s): D

Explanation:

Either statement is sufficient. The ratio of the perimeters of two similar triangles is equal to the ratio of the corresponding sides. Also, the ratio of the areas of two similar triangles is equal to the squares of the ratios of the corresponding sides.



What percent of the class period is over?

(1) The time remaining is 1/4 of the time that has passed.
(2) The class period is 42 minutes long.

  1. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
  2. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
  3. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
  4. The problem can be solved using EITHER statement (1) only or statement (2) only.
  5. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.

Answer(s): A

Explanation:

Let x equal the amount of time passed. Since the time remaining is 1/4 of the time that has passed, this time can be represented as 1/4 x. Converting to decimal form may make this problem easier, so change 1/4 x to .25x. Since 1x is the time passed and .25x is the time remaining, then 1x + .25x is the total time. This is equal to 1.25x. To calculate the percent of the period that is over, use the proportion . Now set up a proportion using the time passed as the part and the total time for the class as the whole.


Cross-multiply to get 1.25x = 100.
Divide both sides by 1.25. x = 80%

80% of the class period is over.
For this particular question, the number of minutes in the class period is not needed to solve the problem.



Between what two numbers is the measure of the third side of the triangle?

(1) The sum of the two known sides is 10.
(2) The difference between the two known sides is 6.

  1. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
  2. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
  3. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
  4. The problem can be solved using EITHER statement (1) only or statement (2) only.
  5. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.

Answer(s): C

Explanation:

The sum of the two smaller sides of a triangle must be greater than the longest side. To find the third side, subtract the two known values to get the lower bound and add the two known values to get the upper bound. The value of the third sides must be between these two numbers. Therefore, both statements are necessary.



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