Answer(s): A
If a straight line were drawn through as many of the plotted points as possible, it would have a negative slope. The line slopes more sharply than the line y = x (a line with a slope of-1), so the line would have a slope more negative than-1. The line would also have a y-intercept well above the x i-axis. The only equation given with a slope more negative than-1is s=-2(t-15).
The radius of the outer circle shown above is 1.2 times greater than the radius of the inner circle. What is the area of the shaded region?
Answer(s): B
The area of a circle is equal to r2. The radius of the inner circle is 5 m; therefore, the area of the inner circle is 25m2. The radius of the outer circle is (1.2)(5) = 6 m; therefore, the area of the outer circle is 36. Subtract the area of the inner circle from the area of the outer circle: 36 25 = 9m2.
If m = 6, then the expression is equal to
Substitute 6 for m:
The expression can be reduced to
Answer(s): D
Factor the numerator and denominator of the fraction:
Which of the following is the vertex of the parabola which is the graph of the equation
Answer(s): C
The equation of a parabola with its turning point c units to the left of they-a xis is written as y=(x + c)2. The equation of a parabola with its turning point d units above the x-axis is written as y= x2+d. The vertex of the parabola formed by the equation y = (x+1)2+2is found one unit to the left of they-a x is and two units above the x-axis, at the point (1, 2). Alternatively, test each answer choice by plugging the x value of the choice into the equation and solving for y. Only the coordinates in choice c, (-1, 2, represent a point on the parabola(y = (x+1)2+2, 2=(-1+1)2+2, 2 = 02+2, 2=2, so it is the only point of the choices given that could be the vertex of the parabola.
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