# Free HESI A2 Exam Braindumps (page: 7)

Page 7 of 156

How many yards are in a mile?

1. 1,000
2. 1,760
3. 5,280
4. 10,000

##### Explanation:

Remember that one mile is equal to 1,760 yards.

1 Mile = 1,760 Yards
1 Mile = 5,280 Feet
1 Yard = 3 Feet
1 Foot = 12 Inches

A rat can finish a maze in about 3 minutes. If a small backpack is put on the rat so it reduces its speed by 50%, how much longer will it take the rat to finish the maze?

1. 3 minutes
2. 6 minutes
3. 10 minutes
4. 12 minutes

##### Explanation:

If the rats speed is reduced by 50%, then it will take the rat twice as long, or 6 minutes. This is 3 minutes longer than it took before.

A nurse's schedule is written in military time, and shows their shift is from 15:00 to 01:00. When will they get off work?

1. Noon
2. Early afternoon
3. Just before midnight
4. A little bit after midnight

##### Explanation:

Converted to regular time, their schedule is 3:00 PM to 1:00 AM. So they will get off at 1:00 AM, which is a little bit after midnight.

Convert 26° Celsius to Fahrenheit.

1. −3.3° F
2. −6° F
3. 46.8° F
4. 78.8° F

##### Explanation:

To convert from Celsius to Fahrenheit you can use this formula: (°C × 9/5) + 32 = °F

Or you can just follow these steps:
1) Multiply by 9
2.) Divide by 5

Page 7 of 156

Post your Comments and Discuss Test Prep HESI A2 exam with other Community members:

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CCNA_owner 3/14/2024 2:12:24 AM
@ Serge 10/17/2023 2:34:12 AM question: QUESTION BEGINING IS BELOW: too (the fixed part is in bold: 2001:db8:0:0000). We borrowed 6 bits so we have to start from two next 00 and add 1 bit to the 6 bits we borrowed for each subnet (6 bits we borrowed are underlined): First subnet: 0000 0000 (binary) = 00 (hexadecimal) Second subnet: 0000 0100 (binary) = 04 (hexadecimal) Third subnet: 0000 1000 (binary) = 08 (hexadecimal) Therefore the third subnet will be 2001:db8:0:0008::/62 or 2001:db8:0:8::/62 in short. Required commands: On Sw101 Sw101(config)#int e0/0 Sw101(config-if)#ipv6 address 2001:DB8:0:8::/62 eui-64 On Sw102 (same commands as Sw101) Sw102(config)#int e0/0 Sw102(config-if)#ipv6 address 2001:DB8:0:8::/62 eui-64 Save the configuration Sw101#, Sw102#copy running-config startup-config
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CCNA_owner 3/13/2024 11:40:21 PM
@ Serge 10/17/2023 2:34:12 AM question: I encounter this lab on exam and have no idea how to solve it: A company plans to deploy 4 new sites. The sites will utilize both IPv4 and IPv6 networks 1. Subnet 10.20.0.0/16 to meet the subnet requirements and maximize the number of hosts • Using the third subnet o Assign the first usable IP address to e0/0 on Sw101 o Assign the last usable IP address to e0/0 on Sw102 2. Subnet 2001:db8::/52 to meet the subnet requirements and maximize the number of hosts • Using the third subnet o Assign an IPv6 GUA using a unique 64-Bit interface identifier on e0/0 on SW101 o Assign an IPv6 GUA using a unique 64-Bit interface identifier on e0/0 on SW102 Any ideas how to approach it? Answer: 64 new sites = 26 -> borrow 6 bits means the first subnet is 2001:db8::/62 Three first octets (2001:db8:0:) have 16 * 3 = 48 bits so they are fixed. 56 – 48 = 8 bits so the next 2 hexadecimal numbers are fixed too (the fixed part is in bold: 20
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